Problem

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: “Hello World” Output: 5

Pre analysis

Will split the words by ‘ ‘ space and count length of last word

Another Solution

let lengthOfLastWord = function(string) {
    let currentStringLength = 0;

    const trimmedString = string.trim();

    const lastIndex = trimmedString.length - 1;

    if (lastIndex === -1) return currentStringLength;

    for (let i = lastIndex; i >= 0; i--) {
        // not getting to this if statement
        if (trimmedString[i] === ' ') {
        return currentStringLength;
        } else if (i === 0) {
        currentStringLength++;
        return currentStringLength;
        } else {
        currentStringLength++;
        }
    }
}